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Solve and graph 3y-2>14
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3y-2>14 +2 +2 3y>16 divided by 3 on both sides. y>(16/3)
Are you missing an x?
No there is no x
Not all the time, if there is only a Y, then the line will be horizontal
<------------> like this at the point y=(16/3).
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As for shading, because y is greater than (16/3), you shade the graph above the line of y= (16/3)
I will draw it for you
If there is no x, what are you plotting it against? y = 16/3 put where?
It's messy, but it works. (16/3) is 5.3333
Plot a dashed line at y=5.333333, and shade above it
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Arrows on both sides <-------> like this
Lines go in both directions of their ends forever
Thank you I struggle a lot in math
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