Geometry help-- picture
Are u familiar with trigo functions like sin, cos n tan? U need to use them to solve this prob.
how???
U can start by writing out the eqn for tan45 in triangle ABC and tan60 in triangle AGE :)
im still confused :/
tan 45 = CB/BA in triangle ABC n tan 60 = EG/AB in triangle AGE okay?
ohk u will have this eq tan 45=58/BA BA=? AG=120-BA tan 60=EG/AG EG=?
\[62\sqrt{3}\]
is this ok?
I got answers but none match..
why non match ha ? EG=62 tan 60 EG=62 sqrt 3
ohhhh. well i feel dumb
ohk so u got it ??
wat the answer u got ?
Well, there's also a more geometric approach instead of this trigonometry thing ur doing
If u notice, the left triangle is a right isosceles triangle which means BC=BA. So 120-58= 62 so AG=62
And u should see the other triangle is a 30-60-90 triangle, and there's a special relation/ratio between the 3 sides. U can look at this website. http://regentsprep.org/regents/math/algebra/ae7/expdecayl.htm And this tells u that GE=62 root 3
@nikato this is the special relation/ratio between the 3 sides
Oops. How embarrassing. Wrong link. http://www.regentsprep.org/Regents/math/algtrig/ATT2/Ltri30.htm
so take this fom the ratio sin 60 /EG = sin 30 /62 which gives u sin 60 /sin 30 = EG/62 sin 60 /cos 60 = EG/62 tan 60 =EG/62 so ull got at the end the same answer
I know ur right,kinda. I mean we got the same answer. But I didn't learn trig yet. So I approached it differently. But I guess it's suppose to be similar Did u get out that link^. It'll tell u the ratio/relations @abbiewinter @ikram002p
yess its good one ^^
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