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Mathematics 21 Online
OpenStudy (anonymous):

Geometry help-- picture

OpenStudy (anonymous):

OpenStudy (superdavesuper):

Are u familiar with trigo functions like sin, cos n tan? U need to use them to solve this prob.

OpenStudy (anonymous):

how???

OpenStudy (superdavesuper):

U can start by writing out the eqn for tan45 in triangle ABC and tan60 in triangle AGE :)

OpenStudy (anonymous):

im still confused :/

OpenStudy (superdavesuper):

tan 45 = CB/BA in triangle ABC n tan 60 = EG/AB in triangle AGE okay?

OpenStudy (ikram002p):

ohk u will have this eq tan 45=58/BA BA=? AG=120-BA tan 60=EG/AG EG=?

OpenStudy (only4u):

\[62\sqrt{3}\]

OpenStudy (only4u):

is this ok?

OpenStudy (ikram002p):

OpenStudy (ikram002p):

OpenStudy (anonymous):

I got answers but none match..

OpenStudy (ikram002p):

why non match ha ? EG=62 tan 60 EG=62 sqrt 3

OpenStudy (anonymous):

ohhhh. well i feel dumb

OpenStudy (ikram002p):

ohk so u got it ??

OpenStudy (ikram002p):

wat the answer u got ?

OpenStudy (nikato):

Well, there's also a more geometric approach instead of this trigonometry thing ur doing

OpenStudy (nikato):

If u notice, the left triangle is a right isosceles triangle which means BC=BA. So 120-58= 62 so AG=62

OpenStudy (nikato):

And u should see the other triangle is a 30-60-90 triangle, and there's a special relation/ratio between the 3 sides. U can look at this website. http://regentsprep.org/regents/math/algebra/ae7/expdecayl.htm And this tells u that GE=62 root 3

OpenStudy (ikram002p):

@nikato this is the special relation/ratio between the 3 sides

OpenStudy (ikram002p):

OpenStudy (nikato):

Oops. How embarrassing. Wrong link. http://www.regentsprep.org/Regents/math/algtrig/ATT2/Ltri30.htm

OpenStudy (ikram002p):

so take this fom the ratio sin 60 /EG = sin 30 /62 which gives u sin 60 /sin 30 = EG/62 sin 60 /cos 60 = EG/62 tan 60 =EG/62 so ull got at the end the same answer

OpenStudy (nikato):

I know ur right,kinda. I mean we got the same answer. But I didn't learn trig yet. So I approached it differently. But I guess it's suppose to be similar Did u get out that link^. It'll tell u the ratio/relations @abbiewinter @ikram002p

OpenStudy (ikram002p):

yess its good one ^^

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