Question

6(square root)10a •3(square root)20a^2

Answer 1

I think this is what you wrote, but what is your question?

Answer 2

Yes @cjr712, but the 5, I changed to 10, it was a mistake.... and I need help solving it.

Answer 3

Is the answer 80(square root) 5x^9?

Answer 4

Oh..... that's wrong.

Answer 5

When a is multiplied by a^2, is it a^3 or a^2?

Answer 6

Oh you changed the problem lol.

Answer 7

a x a^2 = a^3

Answer 8

Ok..so far I got ...18(square root) 200a^3.....from there I need to simplify it.

Answer 9

Now when I simplified.....I got 36a(square root)25a.

Answer 10

But, my teacher said when you multiply square roots u have to solve first, and then simplify.

Answer 11

so the answer should be 180(a)[sqrt2a]

Answer 12

I will write it in my program so you can see what I mean.

Answer 13

Ok.... that will help.

Answer 14

Check it out and let me know

Answer 15

How come you don't simplify starting from 18(square root) 200a^3?

Answer 16

6rt(5x)(3)rt(20a^2)
6rt5rtx.3rt4rt5rta^2
rewrite to group and simplify
(18)(5)(2)(a)(rtx)
180artx

Answer 17

Im still confused.....@kmacdaddy

Answer 18

Well people approach the problem differently. I just did it in a way that you can see how everything is being multiplied and simplified.

Answer 19

Ok so if I di it my way and got 36a(square root)25a.......that is wrong?

Answer 20

What are you confused about?

Answer 21

yeah that is wrong

Answer 22

if you multiply the sqrts you should have 10a*20a^2 right? which is the same thing as 2*100*a*a^2.... the 100 and the a^2 are perfect sqrts so they come outside as 10a and the 2a stays inside the sqrt.

Answer 23

Ok .....when I multiply 6 by 3, I get 18, which goes outside the square root, and then I multiplied the number inside the square root and I got 200a^3. Then, I cubed it, to multiply 8 times 25. Eight can come out as 2, so when multiplied by 18.....it is 36

Answer 24

i was wondering why "x" in an" a" problem
look back 34 mins that's what i started with

Answer 25

Then, the a^3 cubed inside comes out as just a, and the remainder of it stays inside the square root. Which is then 36a(square root) 25a

Answer 26

The problem is that you are doing the sqrt of 200 incorrectly. Everything else you are doing is fine, but the sqrt of 200 is 10[Sqrt2]

Answer 27

How is 10 times 2 largest perfect cube?

Answer 28

its not a cube root it's a square root

Answer 29

But doesn't the a^3 make it a cube root.

Answer 30

the cube root of a^3 is a but the sqrt root of a^3 is asqrta

the cube root of 200 is 2cuberoot25 but the sqrt root of 200 is 10sqrt2

Answer 31

The a^3 doesnt make it a cube root... it is asking you to find the sqrt of a^3

Answer 32

10 times 2 is 20, do you mean 100 times 2.....

Answer 33

if you put the 10 back in the sqrt it becomes 100 again so 100*2=200

Answer 34

Oh ok I understand now......my answer is 180a(square root)2a

Answer 35

yes thats the answer :)

Answer 36

no 180arta not 2a

Answer 37

Thank you all for the help.......even though it took a while for me to understand.😊:D

Answer 38

the 2 stays in the root because 200 = 100*2

Answer 39

@cjr712 and @Haseeb96 is correct.

Answer 40

no review my solution above the x should be an a but follow the factorization

Answer 41

Just saying.

Answer 42

I don't know what math concept u are applying......because I am not familiar with "arta"

Answer 43

you had changed the problem again ok
I had 6rt5x
you did 6rt10a

Answer 44

"arta" is a(square root)a

Answer 45

thank you

Answer 46

Oh ok.....lol.....never heard of that^_^

Answer 47

Thanks again..........@cjr712, @triciaal, @Haseeb96 ......😊