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Mathematics 8 Online
OpenStudy (calculusxy):

MEDAL Someone please help me solve this problem

OpenStudy (calculusxy):

OpenStudy (calculusxy):

@robtobey

OpenStudy (calculusxy):

@agent0smith @Ashleyisakitty @TuringTest

OpenStudy (calculusxy):

@mathstudent55

OpenStudy (kainui):

So first off, what do you think you have to do here? You could try plugging in values of x and see if it gives you true answers.

OpenStudy (mathstudent55):

Substitute each value in the inequality. If it makes the inequality true, it can be a value of x. If it doesn't, it can't.

OpenStudy (mathstudent55):

Don't do anything to the inequality. Just replace x with each value first. Then calculate each side, and see if it's true.

OpenStudy (calculusxy):

I know that that's the most obvious one, but I wanted to know without any substitution. Kind of like using an abstract method.

OpenStudy (mathstudent55):

Here's how you'd check choice A.: 5x + 2 < 2x + 5 A) 0 5(0) + 2 < 2(0) + 5 0 + 2 < 0 + 5 2 < 5 Since 2 < 5 is a true statement, choice A) 0, is good.

OpenStudy (calculusxy):

Any other way instead of substituting the numbers into the variable's place?

OpenStudy (mathstudent55):

If you want to do a little more work at first, but it'll save you work larter, then solve the inequality for x. 5x + 2 < 2x + 5 Subtract 2 from both sides: 5x < 2x + 7 Subtract 2x from both sides: 3x < 7 Divide both sides by 3: x < 7/3 which means x < 2.333333...

OpenStudy (mathstudent55):

Now that you know what x is, check each choice. If the choice is less than 2.333..., then it works. If x > 2.333... then it doesn't work.

OpenStudy (calculusxy):

@mathstudent55 Didn't you add the 2 to 5 in order for it to come to 7? I thought that if you subtract you would get 3.

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