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Mathematics 19 Online
OpenStudy (anonymous):

@superdavesuper

OpenStudy (anonymous):

lets solve here, it'll be easier ok?

OpenStudy (anonymous):

K, so the shortest part is a the middle part is b and the longest c right? would you be able to draw that for me to see that i have the same picture drawn

OpenStudy (superdavesuper):

|dw:1390251515002:dw|

OpenStudy (anonymous):

I guess I'm back, haha. so wanna get back to the question?

OpenStudy (superdavesuper):

I read ur Q again...its kind of complicated...is it multiiple choice?

OpenStudy (anonymous):

yep

OpenStudy (superdavesuper):

OK I will give u the inequality n u check out which choice is right ok?

OpenStudy (anonymous):

sounds good

OpenStudy (superdavesuper):

look at the drawing above: a+b>c do u understand why?

OpenStudy (anonymous):

i actually can't see that drawing, it won't show for me still

OpenStudy (superdavesuper):

Hahahaa okok so a,b,c are the 3 sides and a<b<c do u understand why a+b>c

OpenStudy (anonymous):

yep

OpenStudy (superdavesuper):

Now 5 is the shortest so it is a but 12 can be either b or c so u need to test and see what the range is for the length of the third side

OpenStudy (anonymous):

how would i test it?

OpenStudy (anonymous):

would i use the a^2+b^2=c^2?

OpenStudy (superdavesuper):

a=5 so the ineqality become 5+b<c and b or c can be 12

OpenStudy (superdavesuper):

nope nope that is only good for triangle w a right-angle. sorry!

OpenStudy (anonymous):

oh man this is frustrating

OpenStudy (anonymous):

maybe b should be 12?

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