@superdavesuper
lets solve here, it'll be easier ok?
K, so the shortest part is a the middle part is b and the longest c right? would you be able to draw that for me to see that i have the same picture drawn
|dw:1390251515002:dw|
I guess I'm back, haha. so wanna get back to the question?
I read ur Q again...its kind of complicated...is it multiiple choice?
yep
OK I will give u the inequality n u check out which choice is right ok?
sounds good
look at the drawing above: a+b>c do u understand why?
i actually can't see that drawing, it won't show for me still
Hahahaa okok so a,b,c are the 3 sides and a<b<c do u understand why a+b>c
yep
Now 5 is the shortest so it is a but 12 can be either b or c so u need to test and see what the range is for the length of the third side
how would i test it?
would i use the a^2+b^2=c^2?
a=5 so the ineqality become 5+b<c and b or c can be 12
nope nope that is only good for triangle w a right-angle. sorry!
oh man this is frustrating
maybe b should be 12?
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