Question

Through (−8, −6); perpendicular to the line passing through (−5, 6) and (−1, 4)

Answer 1

Find the slope of the line passing through (−5, 6) and (−1, 4)
m = (y2-y1)/(x2-x1) ---- (1)

Slope of perpendicular line is: - 1 / m

So y = -1/m(x) + b ----- (2) (put m from (1))

The perpendicular line passes through (-8, -6). Put x = -8 and y = -6 above in (2) and solve for b.

Answer 2

thank can I please get a little more details

Answer 3

Slope of the line m passing (−5, 6) and (−1, 4) = (y2-y1)/(x2-x1)
m = (4-6)/(-1-(-5)) = -2/(-1+5) = -2/4 = -1/2
Slope of the perpendicular line = -1/m = -1/(-1/2) = 2

y = mx + b = 2x + b
when x = -8, y = -6
-6 = 2(-8) + b
-6 = -16 + b
b = 16-6 = 10

y = 2x + 10

Answer 4

thank you

Answer 5

you are welcome.