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Mathematics 24 Online
OpenStudy (anonymous):

Estimate f^-1(2) based off the graph attached inside. **not sure how to identify it :/

OpenStudy (anonymous):

graph! :)

OpenStudy (agent0smith):

Properties of inverse functions f^-1(a) = b then f(b) = a f^-1(2) = ? then f(?) = 2

OpenStudy (anonymous):

f(1)=2 ?

OpenStudy (anonymous):

oh wait.. would it be f^-1(2) = -2 then f(-2) = 2 ? :/

OpenStudy (agent0smith):

remember, f(x) is like y... f^-1(2) = ? then f(?) = 2 <=== find this on the graph

OpenStudy (anonymous):

-2?

OpenStudy (anonymous):

oh wait, -1 ?

OpenStudy (anonymous):

because of the point (-1, 2) ?

OpenStudy (agent0smith):

f^-1(2) = ? then f(?) = 2 so you know f(-1) = 2 right? Now you should know f^-1(2) = ....?

OpenStudy (anonymous):

it would be 1 ?

OpenStudy (agent0smith):

f^-1(2) = ? then f(?) = 2 You already found what the ? is.

OpenStudy (anonymous):

-1 ?

OpenStudy (anonymous):

ohh okay :) yay!! thank youuu!! :D

OpenStudy (anonymous):

oh so there's a second part that is kinda linked to this graph... it gives me graphs and asks which one is f^-1 on the same axes... here are graphs 1, 2, and 3 attached

OpenStudy (anonymous):

and here are graphs 4 and 5...

OpenStudy (anonymous):

i'm not really sure how to see which one is f^-1.... it should be below the x axis though right?

OpenStudy (agent0smith):

Easiest way is to draw the line y = x, and see which graph is reflected perfectly over that line (that's how you find the inverse function)

OpenStudy (anonymous):

ohhh okay.. lemme try that..

OpenStudy (anonymous):

umm not 100% sure, but would it be graph 4? because the line y=x would go straight through (0,0) right?

OpenStudy (agent0smith):

Yeah, even by imagining the line y = x i can see it's #4

OpenStudy (anonymous):

oh okay awesome!! thank you so much... again haha!!!! :)

OpenStudy (agent0smith):

:)

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