Simplify ln(1/e) + lnAB

This is a natural log problem right? Not really sure how to start it off though :/

But would the second part of the problem, lnAB, simplify to lnA + lnB ? :/

Question

Simplify ln(1/e) + lnAB

This is a natural log problem right? Not really sure how to start it off though :/

But would the second part of the problem, lnAB, simplify to lnA + lnB ? :/

dumbcow · Answer

yes you are right about lnAB = lnA +lnB

for first part, ln(1/e) = ln(e^-1) = -1*ln(e) = -1

anonymous · Answer

so this becomes:

-1 + lnA + lnB ?

dumbcow · Answer

yes

anonymous · Answer

okay yay :)

so is that as simplified as it can get?

dumbcow · Answer

yeah
well it depends what they mean by simplify, you can't break down the logs any further but you could combine everything into 1 log??
is this combining logs or expanding logs?

anonymous · Answer

not sure... it just says to simplify completely... :/

anonymous · Answer

so would that mean to break it up as much as possible?

dumbcow · Answer

yes i assume so

anonymous · Answer

okay great! thank you :)