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Mathematics
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natural log and the e cancel out
ln e = 1 in other words
just to be sure, does the question have two e? and is the second e an exponent?
what if the second e was a 1?
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something multiplied by 1 is its self but if the problem is ln(e)^e then answer would be e, but if the problem is ln(e) then it would be 1 make sense
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