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Mathematics 19 Online
OpenStudy (anonymous):

Help! photo of problem in comments

OpenStudy (anonymous):

OpenStudy (anonymous):

natural log and the e cancel out

OpenStudy (anonymous):

ln e = 1 in other words

OpenStudy (anonymous):

just to be sure, does the question have two e? and is the second e an exponent?

OpenStudy (anonymous):

what if the second e was a 1?

OpenStudy (anonymous):

something multiplied by 1 is its self but if the problem is ln(e)^e then answer would be e, but if the problem is ln(e) then it would be 1 make sense

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