Question

What is the slope intercept form that passes through the given point and is perpendicular (-6,4), 3y =2x-3? What is the answer?! Help!! :)

Answer 1

slope-intercept form is y=mx+b so you're going to want to take the full equation that you have and divide it by 3

3y=2x-3 becomes y=(2/3)x-1

your slope (m) is 2/3, the slope of a line perpendicular to this one is the negative reciprocal of this slope, which means you flip it and multiply it by -1

the slope of a line perpendicular to this one is then:

-3/2

Now you take your x, y, and m values:

x=-6
y=4
m=-3/2

and plug them into the slope-intercept form

4=(-3/2)(-6) + b

multiply -3/2 by -6 to get 9 (remember, a negative times a negative is always a positive)

you now have 4=9+b

subtract nine from both sides to get b by itself

-5=b

Now re-write the equation with only m and b, leaving x and y as variables:

y = (-3/2)x - 5