Question

Can someone help me with standard form...

Answer 1

write the equation in standard of the line perpendicular to y-1=x+3 passing through point 5,5

Answer 2

standard form is y=mx+b

to solve your equation, you're first going to subtract 1 from both sides, so you'll have:

y = x+4

To find a line perpendicular to a given one, you need to take the negative reciprocal of your slope

Because there is no coefficient (m) in front of x, you know that m=1 (if you have a coefficient of 1, you don't need to write the 1)

1 = 1/1

The negative reciprocal of 1/1 is -1/1 or -1

Now you have your m for your new equation, but you do not know b for this equation

Plug in the point you were given and the m you just found

m = -1
x = 5
y=5

5 = -1*5 + b

5 = -5 + b

add 5 to both sides to get b by itself

10 = b

your final equation is:

y = -x+10