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Mathematics
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Factor by Grouping. I'm not sure if I'm doing this right?
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I ended up with (x-3y)(x-3) But on my online homework they don't give that as an answer choice? They give 5(x-3y)(x-3) but I don't know why? They also give "none of the above" which I'm always afraid to choose as an anser because I'm usually not confident.
5x(x-3y) - 15(x-3y) is a start
you can factor the common factor of 5 out of the whole thing
(5x - 15)(x - 3y) = 5(x-3)(x-3y)
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clear that there is a common factor of 5 there yes?
OH!! Thank you! I totally just had the 5 disappear instead of pulling it out!
yw
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