The weight of a book on an inclined plane can be resolved into two vector components, one along the plane, the other perpendicular to it.
How do you find out that incline angle is zero degrees when the parallel component is equal to zero? And how do you find out that the incline angle is 90 degrees when the parallel component is equal to the weight?

Question

The weight of a book on an inclined plane can be resolved into two vector components, one along the plane, the other perpendicular to it.
How do you find out that incline angle is zero degrees when the parallel component is equal to zero? And how do you find out that the incline angle is 90 degrees when the parallel component is equal to the weight?

lastdaywork · Answer

Try to resolve the "...weight of a book on an inclined plane..." using the angle of inclination in the trigonometric ratios. The answer to you question will then be obvious.

random231 · Answer

uh well the weight vector can be resolved along the plane as mgsin(theta). now when mgsin(theta) is zero implies sin(theta)=0 so theta = 0 degrees. THETA BEING THE ANGLE OF INCLINATION. similarly when mgsin(theta)=mg implies sin(theta)=1 so (theta)= 90 degrees....