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A kite 100 ft above the ground moves horizontally at a speed of 8 ft/s. At what rate is the angle between the string and the horizontal decreasing when 200 ft of string has been let out?
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i already solve it but its wrong....i can´t understand why
well it requires related rates...
you should use tan instead of cos because the diagonal is changing based on the angle
The 200 should not be substituted before taking the derivative.
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yes...i think both answerrs are right....i spenad like 3 hours trying to figured out the mistake....thanks a lot
tan(t) = 100/x sec^2 t' = -100/x^2 * x' t' = -100cos^2 x' / x^2
yes i know how to s olve with tan....is just i want to know the mistake with cos instead of tan
thanks bye
ok :)
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