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y=4x^2+x+1
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Find the x intercept.
Graph: \(y=4x^2+x+1\) Once you have graphed your equation locate the point on the graph where y is zero, and that will be your x-intercept.
put x=0, y=4(0)^2+0+1=1, so point is (0,1)
to find y intercept, for x intercept plug in y=0
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0=4x^2+x+1 There is no x intercept for the graph doesn't touch x-line
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