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Solve, using the substitution method. j + k = 3 j – k = 7 A. The solution is (8, 1) B. The solution is (5, –2) C. There is no solution. D. There are an infinite number of solutions.
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You have j+k=3 and j-k=7, if you change one of the equations so it is equal to one of the missing numbers then you can substitute it into the other equation to solve it. I suggest taking the second equation and adding k to both sides and solving for j.
Sorry, your solving for k not j.
its ok
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