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Solve, using the substitution method. y = 3x + 5 4x – y = 5 A. (10, 35) B. (15, 10) C. There are an infinite number of solutions. D. There is no solution.
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4x –(3x + 5) = 5 4x -3x -5 = 5 1x - 5 = 5 +5 +5 x = 10 4(10) + y = 5 40 + y = 5 -40 -40 y = 35 (10,35)
thanks a bunch
yw
1 more please
@tHe_FiZiCx99
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Solve, using the substitution method. y + 2x = 7 14 – 4x = 2y A. The solution is (1, 5) B. The solution is (21, 0) C. There are an infinite number of solutions. D. There is no solution.
aha have fun fizi
C
thanks again
Here ya go :)
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the answer is A
thanks @lovethecreation
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