How many ways are there that no two students have the
same birth date in a class of 60? note: assume that year is not included in “birth
date”, and you can approximate by not accounting for leap years.

I cant decided if this would be a permutation or combination

Question

How many ways are there that no two students have the
same birth date in a class of 60? note: assume that year is not included in “birth
date”, and you can approximate by not accounting for leap years.

I cant decided if this would be a permutation or combination

anonymous · Answer

any guess?

anonymous · Answer

im leaning towards permutation with he answer being 365!/305!

anonymous · Answer

how many ways can the first person's birth day be? 365, 
to have a different birth as the first person's, the second person can only have 364 days.
third person -> 363
.
.
all the way down to the 60th person.

so that is precisely 365 permute 60, (365P60) which is the same as 365!/305!