Question

What is an equation of the line that passes through (0, 8) and (4, 0)?


y = -2x + 4
y = 2x + 4
y = -2x + 8
y = 2x + 8

Answer 1

Find the slope first with (y2-y1)/(x2-x1)

Answer 2

so whats the answer?

Answer 3

Do you know how to find slope?

Answer 4

no

Answer 5

We have point (x1,y1) which is (0,8) and point (x2,y2) which is (4,0) Plug the into the equation I posted above

Answer 6

idk

Answer 7

(y2-y1)/(x2-x1)

(0-8)/(4-0) = ?

Answer 8

4

Answer 9

-8
---- = -2
4

Answer 10

so whqts the answer i will give you a medal

Answer 11

Now we have to plug -2 (slope) into another equation. I will choose point (0,8).

y-y1=m(x-x1); where y1 is 8, m is -2, and x1 is 0

Answer 12

so its d?

Answer 13

y-8=-2(x-0)

can you solve this for y?

Answer 14

im not sure

Answer 15

y-8=-2(x-0)
y-8=-2x
+8 +8

y=-2x+8