Solve for x. -ax + 3 b > 5
-ax + 3b > 5 -3b -3b -ax > 5 - 3b divided everything by -a x < (-5/a) + (3b/a)
If you want it in as one fraction: x < (3b-5)/a
Now, I can't I have 3b in the front of 5?
Plus, there isn't an answer for that one. I got: x < 3b + 5 over a
(3b/a)-(5/a) = (-5/a)+(3b/a) = (-5+3b)/a = (3b-5)/a
So...the answer is my answer?
3b-5 is all divided by a, not just 5
I know, but there isn't a choice for that answer. :/
@satellite73
@nikato
-ax+3b>5 -3b -3b -------------- -ax>5-3b --- ----- -a -a x<5-3b ------ -a
this is what i got
Same thing as me.
Ok, I'm trusting your answers you guys. Thank you.
(-3b/-a) -> (3b/a)
yea. no problem
Wait
yes?
That's not a solution. Here are the solutions: x > the quantity 3 times b minus 5 all over negative a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over negative a x < the quantity negative 3 times b plus 5 all over negative a
I mean C.
i think its D
why
D is what we both got as the answer.
Ok.
all over -a is (3b-5)/a
Ok, I'm going w/ your answer D.; thank you both.
*all over -a is (3b-5)/-a also: http://www.wolframalpha.com/ This website solves any equation.
So, you're telling me that the answer is D. and I love that website.
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