Medal+Fan. please help. **view attachment in reply below**
problem
One way to solve the problem is to plug in the values to see if they equal each other.
Add 5 to both sides and then square both sides {sqrt(x+6)}^2= (x+6)^2
You can solve the equation and check the solutions in the original equation or you can test the given answers in the equation and see if they make the sentence true.
@Mertsj @cjr712 @KirbyLegs I keep going back to option C. but i dont know. really rusty on all these concepts, its been a year.
sqrt(x+6) = x + 6 when sqrt(A) = A, A is either 0 or 1.
@Mertsj ill just apply each given answer
That's the simplest thing to do in this situation.
when you square a square root, whatever is inside comes out, so you'll have x+6 on the left side and (x+6)^2 on the right side which when you foil out it comes out to x^2+12x+36
@cjr712 i am still stuck with C
That's because it says non extraneous solutions
one of the numbers in C does not work
@cjr712 what do you mean?
@cjr712 ahhhh hold on then. redo.
@cjr712 im not understanding. neither -2 or -6 work.
-6 works
sqrt of 0 is 0 -5 is -5 and -6+1 is -5 so -5=-5
be careful of the wording make sure you understand what they're asking so you can answer correctly
@cjr712 so then it is -2? since it is saying nonextraneous and 2 does not work
-2**
-2 is extraneous since it doesnt work. -6 is non extraneous. that is the meaning of it,
@cjr712 ohh, i reversed their meaning
:)
@cjr712 ty!!
you're welcome
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