Question

What is this equation in standard form? y^2+4y-8x+4=0

I believe the standard form for a hyperbola is (x-h)^2/a^2 - (y-k)^2/b^2=1

I just don't know what terms to put where.

Answer 1

@ikram002p Do you know how to do this?

Answer 2

y^2+4y-8x+4=0
y^2+4y+4-8x=0
(y+2)^2-8x=0
x=(y+2)^2/8
so its parabola

Answer 3

Argh. That's probably why I couldn't make it work in the first place. Thanks!

Answer 4

wlc