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Algebra 19 Online
OpenStudy (anonymous):

Anyone someone help me please

OpenStudy (anonymous):

write your question

OpenStudy (anonymous):

hold up one second

OpenStudy (anonymous):

Here please help me

OpenStudy (anonymous):

Helloo????

OpenStudy (anonymous):

Hellooo?

OpenStudy (anonymous):

that would be B

OpenStudy (anonymous):

Here's two and three

OpenStudy (anonymous):

for the 2nd one; they are point for a particular function, but they are not a function

OpenStudy (anonymous):

for the 3rd one, do you know how to find the inverse of a function?

OpenStudy (anonymous):

I suck at math honestly.

OpenStudy (anonymous):

i can help you with the third one, but i have to leave after that okay

OpenStudy (anonymous):

Thank you (:

OpenStudy (anonymous):

so the original function is f(x) = 2x-2 you can right f(x) as y to make it simple, but they mean the same so y = 2x-2 first step is to switch the y and the x so x = 2y-2 second, solve for y so x = 2y - 2 -- add 2 to both sides +2 +2 ------------------ x+2 = 2y -- divide both sides by 2 to isolate and solve for y (x+2)/2 = 2y/2, simplify x/2+1 = y ---the inverse of the function final step replace the y by f^-1(x) so f^-1(x) = x/2+1--answer

OpenStudy (anonymous):

make sense?

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