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OpenStudy (amoodarya):
\[\sqrt{2x-1}=3\\to \ the \ power \ of \ two \\2x-1=9 \rightarrow2x=10\rightarrow x=5\\check \\x=5 \rightarrow \sqrt{2(5)-1}=3 \\ok\]
OpenStudy (amoodarya):
\[\sqrt{2x-1}+3=0 \rightarrow \sqrt{2x-1}=-3\rightarrow \\2x-1=(-3)^2=9 \\2x-1=9 \\2x=10\\x=5\\check\\ \sqrt{2(5)-1}=3\neq-3\\\]
it hast not solution
OpenStudy (anonymous):
I can't view all of those equation symbol thingies. @amoodarya
OpenStudy (amoodarya):
"thingies" whats that mean ?
OpenStudy (anonymous):
I cannot see the equation symbols.
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OpenStudy (amoodarya):
are you using a computer ? or mobile device
OpenStudy (anonymous):
Computer.
OpenStudy (anonymous):
I got it. Thanks :)
OpenStudy (amoodarya):
really you got it ?
OpenStudy (anonymous):
Wait, no wrong question. I am so confused.
Can you write it again without using equation symbols?
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OpenStudy (anonymous):
@amoodarya
OpenStudy (amoodarya):
OpenStudy (amoodarya):
i send it as a picture
do you see now ?
OpenStudy (anonymous):
Yes! Thank you :)
OpenStudy (amoodarya):
for better understanding
solve these equation
\[\sqrt{x}-x=0 \rightarrow x=0 , 1 \\\]
both of them are correct
\[\sqrt{x}+x=0 \rightarrow x=0 , 1 \]
x=0 ok
x=-1 is not correct