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Mathematics 7 Online
OpenStudy (jacobbirddog):

please help, Will give a medallion as well as a fan!:) Multiply. –2y2 • xy4 A. –2xy8 B. –2xy6 C. 4xy6 D. –2x3y4

OpenStudy (anonymous):

-2y^6x

OpenStudy (jacobbirddog):

so would tht be b?

OpenStudy (jacobbirddog):

i keep on getting b )_)

OpenStudy (anonymous):

Yeah, sorry, the ^ before a number means that it is an exponent

OpenStudy (jacobbirddog):

oh ok :) thank you for clarifying that i was like wtf is that?

OpenStudy (jacobbirddog):

a few more pls

OpenStudy (jacobbirddog):

Write the polynomial 4x2 + x5 – 12 + 6x in standard form. A. –12 + 6x + 4x2 + x5 B. x5 + 4x2 + 6x – 12 C. x2(4 + x3) + 6(x – 2) D. 4x2 + x5 – 12 + 6x

OpenStudy (anonymous):

To put polynomials in standard form, you put them in decending order by the exponents, so it should look like this: x^5+4x^2+6x-12

OpenStudy (jacobbirddog):

sorry i went afk

OpenStudy (jacobbirddog):

i have a few more

OpenStudy (jacobbirddog):

Which expression is a polynomial?

OpenStudy (jacobbirddog):

i keep failing at this one this is a different hw problem btw

OpenStudy (jacobbirddog):

i don't like online homework

OpenStudy (anonymous):

With those four answers, A. is the only one that will work because polynomials cannot have any dividing by a variable (like in answers B. and C.) A polynomial also cannot contain the square root of x because that is a fractional exponent.

OpenStudy (jacobbirddog):

wow...

OpenStudy (jacobbirddog):

thanks i have 2 more >~<

OpenStudy (anonymous):

Okay I will try to help.

OpenStudy (jacobbirddog):

Express the perimeter of the triangle as a polynomial. A. –11x – 5 B. 11x – 4 C. 11x + 4 D. 10x – 5

OpenStudy (anonymous):

For this one you need to add together the like terms so 4x+x+6x=11x and 1+2-7=-4, and our final answer would be 11x-4

OpenStudy (jacobbirddog):

thank you so much!!!!!!!! i keep on getting a -_-

OpenStudy (jacobbirddog):

last question: Simplify the expression. 3^4 • 3^2 A. 3^6 B. 9^8 C. 9^6 D. 3^8

OpenStudy (jacobbirddog):

nvm i finished it thanks for all the help!

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