Question

Plot the stationary and inflection points for f(x)= x^4-3x^3+3x^2+1

Answer 1

To get inflexion point you want to differentiate the function twice can you do that?

Answer 2

Yeah I'm just having trouble getting the points after I differentiate he first time

Answer 3

Okay so if you differentiate
4x^3-9x^2+6x=0
make it equal to 0 to get the stationary points

take our the highest factor

Answer 4

x(4x^2-9x+6)=0

x=0 or
4x^2-9x+6=0

Answer 5

solve for x

Answer 6

Okay I'll try that :)

Answer 7

So the answer I get is 9 plus or minus sqrt of -15all divided by 8

Answer 8

that is correct, so there is one real solution, and 2 complex solutions, ignore the complex,
so it starts when x=0, y=1
that is your coordinate for minimum point which should be a stationary point.