Can someone quickly check 6 questions for me correct me if I did any wrong...I need to finish soon so I just want someone to correct me.
First one is wrong, I'm not sure on the second one. Keep forgetting radicals U.u
Yeah Radicals was the hardest thing for me to learn
Suppose you're given 16 ^ 7/9 The numerator is the exponent of 16 the 9 is the root,
Decent diagram of what it should be.
2 is D.
If u rewrite it, it is 7^1/3 ------- 7^1/5 Using this rule, http://www.regentsprep.org/regents/math/algebra/ao5/rule_pdiv.htm U get 7^2/15
is 1 is A? and thank you Nikato.
Yes 1 is A
Yeah 1 is A
I think you're right, 4 square is 2 and 25 squared is 5
Yea. Both look correct
It's decay because its below 1, anything below 1 is decay.. anything above 0.99 is growth
Okay thank you
np
OHH WAIT I was confused!! See the y intercept of g(x) is when x is 0, when x is 0, the y intercept is left alone :D So because the y intercept of f(x) is 3 and the y intercept of g(x) is 6 then its 2 times the y intercept of f(x). 3 * 2 = 6
The y intercept of g(x) is 2 times the y intercept of f(x) ._.
Wait so when there is a 0 the y intercept is left alone?
When x is 0, thats how you find the y intercept. To find the y intercept, set x for 0 To find the x intercept, set y for 0
Suppose your asked to find the y intercept of 3x + 2y = 12 Set x for 0, 3(0) + 2y = 12 /2 /2 y = 6 You can pretty much find the x from plugging in your y, 3x + 2(6) = 12 3x + 12 = 12 -12 -12 3x = 0 /3 /3 x = 0 3(0) + 2(6) = 12 0 + 12 = 12 12 = 12 :D
Okay thank you this is very helpful! You're really good! I'm so sorry to bother you but i have to get a good grade on this mind checking like 2 more? so sorry!!
Sure, i gtg soon :p like next 10 min
What did you put for number 5?
C
C is correct. the first function is f(x)=5^2 second is g(x)=-3 and then together 5^2 -3
for the other one, change it to slope intercept form and grpah it so y=-3x+10. can u try grphing this?
yes
Is it C? sorry I might have graphed it wrong.. I am not really good at this.
no. its not right. however part of it is right. the graph does not contain the origin, however, it should be a slolid line when grapging, the >= sign means solid line where as just > means dotted line
Ohh thank you!! (:
yea. and just to let u know, ur graph should have look something like this
oh nevermind, but if u want to look at it, just type in ur function
Okay thanks
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