Question

k+12=3k
Show work.

Answer 1

k=6

Answer 2

k + 12 = 3k
-k -k

12 = 2k
/2 /2

k = 6

6 + 12 = 3(6)

18 = 18

Answer 3

Solve for k:
k+12 = 3 k
Move terms with k to the left hand side.
Subtract 3 k from both sides:
(k-3 k)+12 = 3 k-3 k
Combine like terms in k-3 k.
k-3 k = -2 k:
-2 k+12 = 3 k-3 k
Look for two terms that sum to zero.
3 k-3 k = 0:
12-2 k = 0
Isolate terms with k to the left hand side.
Subtract 12 from both sides:
(12-12)-2 k = -12
Look for two terms that sum to zero.
12-12 = 0:
-2 k = -12
Divide both sides by a constant to simplify the equation.
Divide both sides of -2 k = -12 by -2:
(-2 k)/(-2) = -12/(-2)
Any nonzero number divided by itself is one.
(-2)/(-2) = 1:
k = -12/(-2)
In -12/(-2), the numbers 12 in the numerator and -2 in the denominator have gcd greater than one.
The gcd of 12 and -2 is 2, so -12/(-2) = -(2×6)/(2 (-1)) = 2/2×(-6)/(-1) = (-6)/(-1):
k = (-6)/-1
Cancel common terms in the numerator and denominator of (-6)/(-1).
(-6)/(-1) = (-1)/(-1)×6 = 6:
Answer: |
| k = 6

Answer 4

^ Did you get that from wolfram alpha?

Answer 5

the souloution no the explaination yes

Answer 6

._.

Answer 7

what lol