How do I solve this system of equations algebraically? (Will give medal & fan) 10x + 4y = 24 -6x - 4y = 8
If I'm correct... your suppose to cancel y out 1st since it's easier to get x. so it will be 4x=-16
Divide it by 4 and you will get x which will be x=-4
Plug in x for any of those equations then subtract it from the sum
Like so, -6 x 4 = -24-4y=8
24+8 = 32
Wait, the most we can do is just move y to the other side, right? we can't just get rid of it. so it would either be 10x = 24 - 4y for the first one or -6x = 8 + 4y for the second one.. right?
Divide by -4 which would be -8
You have to get rid of one to find the 1st one
@phi
You can only do it if they cancel out. Which is why y was canceled out.
I just don't understand...
y= -8 x=-4
I don't know how to explain it better than that :\ Sorry if I wasn't any help
I graphed the system on a graphing calculator, so I know the solution is x = 8 and y = -14, I just don't know how to get it by doing the math
.... Well idk
10(8) + 4(-14) = 24 80 + (-56) = 24 24 = 24
-6(8) - 4(-14) = 8 -48 - (-56) = 8 8 = 8
I just still need to be shown how to solve it algebraically... as if i never graphed it.. for anyone who wants to help...
I don't know how to solve it algebraically, but I graphed it and the answer is (8, -14)
Lol, I just saw that you knew that already...
10x + 4y = 24 -6x - 4y = 8 You would first cancel out the 4y's to solve for x, then add the equations together. You would then have the equation 4x=32.
Once you have that you would then divide both sides by 4.
how do you cancel out the ys?
Then you take that number and one of the equations and plug it in for x.
Its simply adding 4y to -4y which equals 0
So then it would be -6 = 8 + 4y though, right?
you can't just add it to one side...
No, you want to get rid of one to solve for the other.
But... you can't just do something to one side and not the other.
Yes you can, its called elimination.
Let me show you....
I've always been taught that you can't do something to one side and not the other, not in algebra.
If you add 4y to one side, you have to add 4y to the other side of the equation as well.
10x + 4y = 24 -6x - 4y = 8 4y+(-4y)=0 10x=24 + -6x=8 4x=32 X=8
Your eliminating so you can solve for x then you are going to use that answer to solve for y.
I just don't even.... I was never taught anything like that.
It will be much easier once you learn that. Then things become less confusing.
I just don't know if I'll get credit for showing work I was never taught...
But I do see how it works... sorta
You cant solve it by moving them to different sides.
Its literally impossible to do that.
Oh okay, I see now, I went through my notes and found something similar
Thank you
Your welcome! :)
I am sure they taught you two ways to solve these equations one way is substitution. The other is elimination. elimination (in my opinion) is easier, especially if you have more than 2 equations and 2 unknowns.
I already figured this problem out, I forgot about the other method but then found something similar in my notes after a little bit of digging. I do need help on a different problem now though.
10x + 4y = 24 -6x - 4y = 8 in this problem, right away I notice a +4y in the first equation and a -4y in the 2nd equation... that is a clue to use elimination. Here is the idea: the left side of eq 1 is equal to 24 the left side of equation 2 is equal to 8 if we add the left sides of the equations, the sum will be 8+24= 32 so let's do that: 10x + 4y + -6x + -4y= 32 (we are doing this because we know 4y + -4y is 0, and y is gone!) 10x - 6x simplifies to 4x and we get 4x = 32 x= 8 now use either of the equations to find y
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