Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Can someone plz help me with a few questions (algebra 2)

OpenStudy (anonymous):

OpenStudy (anonymous):

@wolfe8

OpenStudy (aravindg):

Use the remainder theorem!!

OpenStudy (aravindg):

If f(x) is divided by (x-a) then the the remainder is f(a).

random231 (random231):

can u do the rest?

OpenStudy (anonymous):

are you sure, they didn't mention that in my lesson?

OpenStudy (aravindg):

I am sure :)

OpenStudy (anonymous):

k

OpenStudy (aravindg):

You will notice that you get the same answer by long division process.

OpenStudy (anonymous):

oh ok

OpenStudy (aravindg):

The remainder theorem gives you the answer in a single step ;)

OpenStudy (anonymous):

oh, cool!

random231 (random231):

yeah ure right ofcourse @AravindG

OpenStudy (aravindg):

:)

OpenStudy (anonymous):

so how does it work with my problem

OpenStudy (aravindg):

If f(x) is divided by (x-a) then the the remainder is f(a). HERE f(x)=given polynomial. a=1 So f(a)= the remainder

random231 (random231):

well put 1 in place of x in the given function!

OpenStudy (aravindg):

ie just put x=1 and you will get the answer.

OpenStudy (anonymous):

sorry im still confused.... could you plug in the numbers and let me solve it?

OpenStudy (aravindg):

Simply put x=1 in the polynomial! dont expect us to do all the work!

OpenStudy (anonymous):

oh, i thought yall were saying something totally different! lol

OpenStudy (aravindg):

lol

OpenStudy (anonymous):

i got -1

OpenStudy (aravindg):

Great! good work!

OpenStudy (anonymous):

thx

OpenStudy (aravindg):

yw :)

OpenStudy (anonymous):

OpenStudy (aravindg):

Post your qns separately.

OpenStudy (anonymous):

would i use a 3 instead of 1 this time?

OpenStudy (aravindg):

Use -3

OpenStudy (anonymous):

i see thx

OpenStudy (aravindg):

It should be of form (x-a) Here its (x+3)=(x-(-3)) So a=-3

OpenStudy (anonymous):

thats all i needed

OpenStudy (aravindg):

great :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!