How do I solve this equation for x? (Will give medal & fan)

10 = 3^(x+5) - 2

Question

How do I solve this equation for x? (Will give medal & fan)

10 = 3^(x+5) - 2

anonymous · Answer

1) add 2
2) take natural lot
3) use log rule
4) divide ln(3)
5) subtract 5

:DDD

anonymous · Answer

I don't know what the log rule is ):

anonymous · Answer

And 4 isn't an answer option for this

agent0smith · Answer

@cutrightceo  try plugging in x=4:
10 = 3^(4+5) - 2
10 = 3^9 - 2
10 = 19681

is 10 equal to 19,681??


Take logs of both sides (add 2 to both sides first): 
log12 = log3^(x+5) 
now you can bring down the exponent

log12 = (x+5)log3

anonymous · Answer

so 1.079 = (x + 5)0.477

anonymous · Answer

I think I can solve it from here (: thank you!

anonymous · Answer

final answer I got is -2.738 (rounded to the nearest thousandth)

agent0smith · Answer

http://www.wolframalpha.com/input/?i=10+%3D+3%5E%28x%2B5%29+-+2+real+solution

anonymous · Answer

Okay (: thank you