Question

If f(x) = log2 (x + 4), what is f−1(3)?

Answer 1

Given the function f(x) = 0.5(3)x, what is the value of f−1(7)?

0.565

1.140

1.771

2.402

Answer 2

If "f-1" the inverse function in the first problem, then
to find f^-1(3) you need to set the left hand side to 3 and solve for x.
f(x) = log2 (x + 4)
3 = log2 (x + 4)
(x+4) = 2^3 = 8
x = 8 - 4 = 4

So f^-1(3) = 4.

Answer 3

the x next to the (3) is an exponent

Answer 4

Given the function f(x) = 0.5(3)x, what is the value of f−1(7)?

0.565

1.140

1.771

2.402

Answer 5

f(x) = 0.5(3)^x, what is the value of f−1(7)?
7 = 0.5 * (3)^x
7/.5 = (3)^x
14 = 3^x
log(14) = x * log(3)
x = log(14) / log(3) = 2.402

Answer 6

I figured the other one out can you help with this one

Answer 7

can you help me with
2 more

Answer 8

Given the parent functions f(x) = log10 x and g(x) = 5x − 2, what is f(x) • g(x)?

f(x) • g(x) = log10 x5x − 2

f(x) • g(x) = log10 (5x − 2)x

f(x) • g(x) = 5x log10 x + 2 log10 x

f(x) • g(x) = 2 log10 x − 5x log10 x