Carson drives to school the same way each day and there are two independent traffic lights on his trip to school. He knows that there is a 30% chance that he will have to stop at the first light and an 80% chance that he will have to stop at the second light. What is the probability that he will NOT have to stop at either light?
@Mathbreaker

Question

Carson drives to school the same way each day and there are two independent traffic lights on his trip to school. He knows that there is a 30% chance that he will have to stop at the first light and an 80% chance that he will have to stop at the second light. What is the probability that he will NOT have to stop at either light?
@Mathbreaker

bibby · Answer

What are the separate probabilities of not stopping at each stoplight?

anonymous · Answer

As these are consecutive events, the probability of the first even happening is 3/10, therefore it not happening would be 7/10. Which is followed by 8/10 chance of stopping at the second one, it not happening would be 2/10.
multiply those two to get 14/100
therefore its 14% :)