Will fan you!! Write each expression using the base only A. 9^-8 x 9^-2 x 9^10 B. 5^4 x 5^7 C. 5^-5 x 5^7
when adding exponents i get 9^0 ....
really it is 9^10 / (9^8 * 9^2).... i took the negative exponents and put them in the denominator ...
i dont get it :/
any negtive exponent say 9^-8 is the same as writing 1/9^8
Alright i get that how do you get am answer though
simplifying it should be 9^10/ 9^10 which cancels 1/1 = 1 but can be written as 9^0 = 1
alright so B. would be 5^11?
yeah that's what i got
if u had (5^4)^3 u would mulitply them so it would be 5^12
sweet! and C im haveing a hard time with that one
if ur asked that (5^4)^3 another way is u can think of it as 5^4 *5^4 *5^4 then u rewrote it like the others so u can just add them now and u get the same answer 5^12
yeah i get that, but what about 5^-5 x 5^7
the expression can be rewritten as 5^7/5^5
so it's like 5 * 5 * 5 * 5 * 5 *5 *5 / 5 * 5 * 5 * 5 *5 so u cancel5 of them and u get 5^2 /1 so 5^ 2 if simplified would be 25
SO pretty much leave 5 alone then add^-5 and ^7 youd get ^2 then you have 5^2 then you add that?
yes, but the 5^2 is 5 * 5 = 25
when the problems deal with more variables then it's a lot easier to make a mistake if not rewritten and worked out in serveral steps
Yeah thats what i meant ha thanks!
it's cool glad i could help.
Wanna help a little more?
well i can try but i don't know it all
Its ok its pretty basic
A. (y^-3)^6 B. (-h^4)^5 C. (t^-4)^-9t^2 D. (5t^3)^-4
so( y^3)^6 is same thing as y ^3*6 = y^18
ok i see how you did that so B would be -h^20?
yes but if it were (-h^4)^4 it would be positive h^16
-1^5 remains negative lot of mistakes are here
so -1^4 would be positive
Alright
is question c written like that? (t^-4)^-9t^2?
yeah it is
so on part d can be rewrttten as 5^-4 * t^3*-4 then rewrtten as 1/ 5^4 t^12
can be simplified 1 / 625t^12
i actually get that haha
we didn't do C
so t^-4*-9t^2 = t^36t^2 i think that is the answer
abc
sorry
Join our real-time social learning platform and learn together with your friends!