Question

Anybody good at Algebra 3?

Answer 1

Input the equation of the given line in standard form. The line with m = -1/2 and the point (-2, -3).

Answer 2

im not but I can guess you the wrong answer

Answer 3

:)

Answer 4

standard form = ax+by = c
first put the equation in point slope form y-y1=m(x-x1)
m = the slope
then put it into standard form

Answer 5

ax + by = c. How do I figure out what the letters are? @helpme1.2

Answer 6

like i said, first you need to input it in point slope form
then it will get easier

y+3 = -1/2(x+3)--distrubute the -1/2
y+3 = -1/2x-3/2 -- subtract 3 to both sides
y = -1/2x-9/2

now for last step put y = -1/2x-9/2 into the standard form

Answer 7

We are given m=-1/2 and the point (-2,-3).
The point-slope form of the equation of this line is thus y-(-3) = (-1/2)(x-[-2]), or
y+3 = (-1/2)(x+2).
Clear out the fractions by multiplying both sides of the equation by 2:

2y+6=-(x+2) = -x - 2.

Add +x to both sides. Subtract 6 from both sides.

Simplify.

Answer 8

Is this still the problem on which you wish to focus?

Answer 9

Yes! I just can't seem to get it... :|

Answer 10

Please look at my previous comments; can you finish the work as I asked?

Answer 11

x + 2y = -8.