Please help, need to move this graph to the right!! (Comments) MEDAL
I need to make this graph (which is sqrt(3x-x^2)
Look like this, I've tried everything. Adding, subtracting...nothing works. Please help!
What do the directions for the problem say?
The function f(x)=sqrt(3x-x^2) is given graphed below: The first graph I posted. A)Starting with the formula for f(x), find a formula for g(x), which is graphed below: The second graph I posted.
y=a(x-1)(x-4) If you substitute the third point from the graph which is (2 1/2, 3) you find that a is -4/3 So the equation is y = -4/3(x-1)(x-4)
Are you sure? I graphed your equation and it didn't give me g(x). I added this to yours: 1.7sqrt(-4/3(x-1)(x-4)) but whenI submitted it was still considered wrong.
But it's going downwards to infinity?
Could it be: 1.75sqrt(-4/3(x-1)(x-4)) seems accurate. But I'm not sure.
The part that is above the x axis seems to be correct. Somehow we need to exclude the part below the x axis. Maybe by squaring and then g(x) would be the sqrt ?
I graphed (and I zoomed in) 1.732sqrt(-4/3(x-1)(x-4)) it seemed spot on. Thoughts, please?
Looks good. Where did you come up with sqrt3 for the constant?
I used sqrt() because it elminated the lines that went downwards. I just got it from the original equation.
Where did you get 1.732 which is sqrt3?
Oh, I know multiplying to the equation stretches it vertically. So...I started 1, then went to 2. Tried everything in between. Educated guess.
So actually you have 2sqrt(-(x-1)(x-4))
The answer I submitted and was accepted: 1.732sqrt(-4/3(x-1)(x-4)) :p
Do you see that what I posted is the simplified form of that?
Thank you. Your equation really made it happen.
yw.
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