Hello I am in Algebra 1 takening the 2nd half this school year with Connections academy, I am working on some extra credit points. Right now Im working on the quadratic functions and equations practice #4. Find the axis of symmetry for y=5x^2-7x+2. Could someone please explain how to come to the correct answer?? Thanks!
half way between the x intercepts is the axis of symmery
Okay I imput the equation into a graphing calculator and the answers came out to be 0.7,-0.45
I get x = 7/10
not sure where you're getting the -.45
Thats what the graphing calc gave me. The test says x= 7/10 i think the -.45 is the y part of it Im not sure
This is a parabola. You can complete the square and find the x-axis of the vertex and a vertical line through the vertex will be the axis of symmetry. It is x = -b/2a = 7/10
okay that sorta makes sense
Yes the vertex is at (0.7, -0.45)
but it only let me choose one, so the axis of symmetry would be x and x would be 7/10
The equation for the axis of symmetry is x = 7/10
okay that makes sense, i think i've got it
Thanks everyone :3
Your welcome.
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