HELPP
Felipe's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Felipe $5.65 per pound, and type B coffee costs $4.55 per pound. This month, Felipe made 148 pounds of the blend, for a total cost of $761.40 . How many pounds of type B coffee did he use?
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OpenStudy (anonymous):
two variables involved....one equation
thus cannot be solved by normal algebra and try to do that by hit and trial
OpenStudy (anonymous):
How many pounds of type B?
OpenStudy (skullpatrol):
Felipe made pounds of the blend? How many?
OpenStudy (anonymous):
148
OpenStudy (anonymous):
no its there
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OpenStudy (skullpatrol):
Yeah, NOW
OpenStudy (anonymous):
ohh darn
OpenStudy (anonymous):
well
OpenStudy (anonymous):
let the pounds of A be x
and for B be y
5.65x + 4.55y= 761.40
x+y= 148
OpenStudy (skullpatrol):
($5.65 per pound)*A + ($4.55 per pound)*B = for a total cost of $761.40
A + B = 148 pounds of the blend
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OpenStudy (anonymous):
ok..
OpenStudy (anonymous):
74?
OpenStudy (skullpatrol):
If you solve for A too, you can check your own answer, right?
OpenStudy (anonymous):
so is it 74
OpenStudy (skullpatrol):
@kaylee.carmestro are you not interested enough to solve for B and check your own answer?
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OpenStudy (anonymous):
yesss
OpenStudy (skullpatrol):
Check your results with the words of the problem, Give the answer.
You will gain confidence that way too :-)