Help with three math problems!
help me @shamil98
determine the value of k first for the direct variation. k = y/x
y = kx so after you determine k , input the values and evaluate.
Can u plug in the numbers? this is confusing
Shamil has shared with you the correct form of the equation for direct variation. y=kx. Now please substitute x=-6 and y=-3 into that equation. Solve the result for k.
ok let me solve it and then will u verify my answer?
Sure, if you act fast!
So i have =3=-6(x) what do i do from here?
-3 divided by -6?
Solve the result for k (not x). Please try this yourself.
-0.5?
2y-6=8x+4 2y=8x+10 y=4x+5 y'=4
luba: why (-)?
oh ur right not negative
so just 0.5?
what would be the constant of variation?
So, luba, k=.5. yes. Now take that same equation again: y=kx. Substitute k=0.5. What will the equation now look like?
-3=6(.5)
oh the 6 is negative
so -3=-6(0.5)
correct?
do u mind telling me the constant of variation?
Take your time; accuracy is more important than speed. Is that equation of yours correct or not? You can judge that yourself.
You have already found the constant of variation; it is k=0.5
oh alright! plz is my equation correct
Is -3=-6(0.5) true or false?
true
Yes; you didn't need to ask me whether it was correct or not; you know how to decide that for yourself.
Now you know k. Substitute your k value into y = kx to obtain a general relationship between y and x.
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