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Mathematics 21 Online
OpenStudy (anonymous):

please solve #27

OpenStudy (anonymous):

OpenStudy (anonymous):

can u help @HelpBlahBlahBlah

OpenStudy (anonymous):

@poopsiedoodle

OpenStudy (helpblahblahblah):

ill try

OpenStudy (poopsiedoodle):

multiply both fractions by 4. x+3 = 7x/2

OpenStudy (poopsiedoodle):

then multiply both sides by 2. 2x + 6 = 7x

OpenStudy (poopsiedoodle):

subtract 2x from both sides. 6 = 5x

OpenStudy (poopsiedoodle):

divide by 5. x = 1.2

OpenStudy (anonymous):

can u help with a few more?

OpenStudy (poopsiedoodle):

sure :3

OpenStudy (anonymous):

OpenStudy (anonymous):

r u still there

OpenStudy (anonymous):

@poopsiedoodle

OpenStudy (poopsiedoodle):

oops. Just saw it :p

OpenStudy (poopsiedoodle):

which one do you need?

OpenStudy (anonymous):

all three but u dont have to do it if u dont have time

OpenStudy (poopsiedoodle):

k, for the first one, a can be 1.5 at the lowest. The highest it can be is 2.499999999999999999999999999999 with lots of 9s.

OpenStudy (anonymous):

so how would i answer this??

OpenStudy (poopsiedoodle):

I think 1.5<_(less than or equal to)a<_2.49

OpenStudy (anonymous):

ok how about the next one?

OpenStudy (poopsiedoodle):

I'm not good with stuff like #35, but I can do #36.

OpenStudy (anonymous):

ok

OpenStudy (poopsiedoodle):

for #36, it's x<2 or (I think that's the giant U) 6<x. I don't remember how to graph it though.

OpenStudy (poopsiedoodle):

@tHe_FiZiCx99

OpenStudy (poopsiedoodle):

maybe he can help :p

OpenStudy (anonymous):

ok(:

OpenStudy (the_fizicx99):

which one is it ._.

OpenStudy (anonymous):

if u could solve 35 and 36 i would really appreciate it

OpenStudy (the_fizicx99):

Ahhh ok, 8-3x ≥ 7 or 6x + 2 >26 Solve for x, sub 8 from both sides, 8 -3≥7 -8 -8 -3x ≥ -1 /-3 /-3 x ≤ 0.33 6x + 2 > 26 -2 -2 6x > 24 /6 /6 x > 4 So you have x ≤ 0.33 OR x > 4 When its OR they're point away from each other. After you plot them it should look like this,

OpenStudy (anonymous):

could u do 36?

OpenStudy (anonymous):

????

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