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OpenStudy (anonymous):
OpenStudy (anonymous):
can u help @HelpBlahBlahBlah
OpenStudy (anonymous):
@poopsiedoodle
OpenStudy (helpblahblahblah):
ill try
OpenStudy (poopsiedoodle):
multiply both fractions by 4. x+3 = 7x/2
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OpenStudy (poopsiedoodle):
then multiply both sides by 2. 2x + 6 = 7x
OpenStudy (poopsiedoodle):
subtract 2x from both sides. 6 = 5x
OpenStudy (poopsiedoodle):
divide by 5. x = 1.2
OpenStudy (anonymous):
can u help with a few more?
OpenStudy (poopsiedoodle):
sure :3
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OpenStudy (anonymous):
OpenStudy (anonymous):
r u still there
OpenStudy (anonymous):
@poopsiedoodle
OpenStudy (poopsiedoodle):
oops. Just saw it :p
OpenStudy (poopsiedoodle):
which one do you need?
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OpenStudy (anonymous):
all three but u dont have to do it if u dont have time
OpenStudy (poopsiedoodle):
k, for the first one, a can be 1.5 at the lowest. The highest it can be is 2.499999999999999999999999999999 with lots of 9s.
OpenStudy (anonymous):
so how would i answer this??
OpenStudy (poopsiedoodle):
I think 1.5<_(less than or equal to)a<_2.49
OpenStudy (anonymous):
ok how about the next one?
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OpenStudy (poopsiedoodle):
I'm not good with stuff like #35, but I can do #36.
OpenStudy (anonymous):
ok
OpenStudy (poopsiedoodle):
for #36, it's x<2 or (I think that's the giant U) 6<x. I don't remember how to graph it though.
OpenStudy (poopsiedoodle):
@tHe_FiZiCx99
OpenStudy (poopsiedoodle):
maybe he can help :p
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OpenStudy (anonymous):
ok(:
OpenStudy (the_fizicx99):
which one is it ._.
OpenStudy (anonymous):
if u could solve 35 and 36 i would really appreciate it
OpenStudy (the_fizicx99):
Ahhh ok,
8-3x ≥ 7 or 6x + 2 >26
Solve for x,
sub 8 from both sides,
8 -3≥7
-8 -8
-3x ≥ -1
/-3 /-3
x ≤ 0.33
6x + 2 > 26
-2 -2
6x > 24
/6 /6
x > 4
So you have x ≤ 0.33 OR x > 4
When its OR they're point away from each other.
After you plot them it should look like this,
OpenStudy (anonymous):
could u do 36?
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