Solve each system using elimination.
3x+3y=27
x-3y=-11
9. 2x+4y=22
2x-2y=-8
11. 5x-y=0
3x+y=24
Please show your work!! Thank you!!
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OpenStudy (usukidoll):
first one add the y's and solve for x.. then plug back the x to find the y
OpenStudy (anonymous):
3x + 3y = 27
x - 3y = -11
3y cancels out
3x + x = 27 + -11
4x = 16
there x = 4.
Sub that into equation (2).... x -3y = -11
4- 3y = -11
-3y = -15
there fore y = 5.
x =4, y =5
OpenStudy (anonymous):
Thank you soo much @BizPro
Can you help me with the others??
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jimthompson5910 (jim_thompson5910):
for #9, my hint is to multiply everything in equation 2 by 2 to go from this
2x-2y=-8
to this
4x-4y=-16
------------------------
we now have this system
2x+4y=22
4x-4y=-16
notice how we haev +4y in the top and -4y in the bottom. They add to 0y, aka 0, and go away and the y terms are eliminated when you add the equations of this new system
2x+4y=22
4x-4y=-16
----------
6x + 0y = 6
So 6x = 6 ----> x = ????
OpenStudy (anonymous):
x=1?
jimthompson5910 (jim_thompson5910):
Good, now take that value of x and plug it into any equation that has x and y in it.
From there solve for y
jimthompson5910 (jim_thompson5910):
For instance,
2x+4y=22
2*1+4y=22 ... plug in x = 1
2 + 4y = 22
...
...
...
y = ???
OpenStudy (anonymous):
Does y=-4??
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jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
try it again
OpenStudy (anonymous):
I am confused..
jimthompson5910 (jim_thompson5910):
2 + 4y = 22
4y = 22 - 2
4y = 20
y = ???
OpenStudy (anonymous):
In the first equation..2x+4y=22 we got that x=1.
Not to figure out why, I must plug in x into 2x-2y=-8, right?
I plugged it into that equation and my answer came out to be y=-4
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No matter which equation you pick, you should get the same answer for y.
OpenStudy (anonymous):
-5
jimthompson5910 (jim_thompson5910):
closer, but no
jimthompson5910 (jim_thompson5910):
-2y = -10
y = -10/(-2)
y = 5 ... it's positive since the negatives cancel
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jimthompson5910 (jim_thompson5910):
4y = 20
y = 20/4
y = 5 ... same answer
OpenStudy (anonymous):
Okay, can you please help me with the next question?
jimthompson5910 (jim_thompson5910):
Add the equations to get
5x-y=0 ... notice how the y terms are equal yet opposite
3x+y=24 ... notice how the y terms are equal yet opposite
---------
8x + 0y = 24
8x = 24 ----> x = ???
OpenStudy (anonymous):
x=3
jimthompson5910 (jim_thompson5910):
Now use that to find y
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OpenStudy (anonymous):
Am I doing this right?
3(3)+y=24
9+y=24
9y=24
jimthompson5910 (jim_thompson5910):
9+y does NOT turn into 9y
jimthompson5910 (jim_thompson5910):
9y means "9 times y" and it's completely different from 9+y
OpenStudy (anonymous):
Okay...So then how would I do it? I am lost right now.
jimthompson5910 (jim_thompson5910):
hint: 9+y is the same as y + 9
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jimthompson5910 (jim_thompson5910):
so
9+y=24
is the same as
y + 9 = 24
OpenStudy (anonymous):
oh..do I switch around the equation? y=24+9?
jimthompson5910 (jim_thompson5910):
no, you need to move that +9 over
jimthompson5910 (jim_thompson5910):
so what must you do to both sides?
OpenStudy (anonymous):
divide or subject?
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jimthompson5910 (jim_thompson5910):
which operation undoes addition?
OpenStudy (anonymous):
subtract, sorry. I mixed up the word with subject
jimthompson5910 (jim_thompson5910):
it's ok
jimthompson5910 (jim_thompson5910):
which operation undoes addition?
OpenStudy (anonymous):
now Y equals 24-9
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OpenStudy (anonymous):
y=15
jimthompson5910 (jim_thompson5910):
good
OpenStudy (anonymous):
wow! Thank you soo much for your help! Can you help me with a few more?
jimthompson5910 (jim_thompson5910):
I can help with one more
OpenStudy (anonymous):
Okay. 12x+2y=90
6x+2y=60
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jimthompson5910 (jim_thompson5910):
notice if you add the equations, the y terms will be 2y+2y = 4y, which is NOT 0y or 0 like we want.
We can fix this by changing the signs of each term in either equation. So change the signs of each term in the second equation to get -6x - 2y = -60. Now add the equations
12x + 2y = 90
-6x - 2y = -60
--------------
6x + 0y = 30
Notice how the y terms are gone now leaving us with
6x = 30
x = ??
OpenStudy (anonymous):
x=5
jimthompson5910 (jim_thompson5910):
Now use it to find y
OpenStudy (anonymous):
y=15
jimthompson5910 (jim_thompson5910):
good
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OpenStudy (anonymous):
I have 3 more of the equations left, can I work them through and you just watch to make sure I am doing them right?
jimthompson5910 (jim_thompson5910):
Sure I can do that. Go ahead
OpenStudy (anonymous):
Thanks. Okay, the first one is 2x+3y=9
x+5y=8
OpenStudy (anonymous):
2x+3y=9
x +5y=8
_________
2x+8y=17
Is that right so far?
jimthompson5910 (jim_thompson5910):
well first off, 2x + x is 3x (not 2x)
and notice how 3y + 5y = 8y which is not 0y or 0
We want either the x or y terms to be eliminated. This doesn't happen here.
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jimthompson5910 (jim_thompson5910):
What can you do to fix this?
OpenStudy (anonymous):
Okay, let me try again.
2x+3y=9
x -5y=8
_________
3x+0y=17
Now is that right?
jimthompson5910 (jim_thompson5910):
now 3y + (-5y) = -2y which is still not 0y
jimthompson5910 (jim_thompson5910):
also, you need to do the same thing for all terms in the second equation (you cannot just change the sign of one term)
OpenStudy (anonymous):
I don't know what to do now.
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jimthompson5910 (jim_thompson5910):
we have 2x in the top equation and an 'x' in the bottom equation
why not multiply that x in the bottom equation by -2 to get -2x
now notice how 2x + (-2x) = 2x - 2x = 0x = 0
jimthompson5910 (jim_thompson5910):
So what you have to do is multiply everything in equation 2 by -2 to get
x+5y=8
-2*x + (-2)(5y) = -2*8
-2x - 10y = -16
jimthompson5910 (jim_thompson5910):
This means the system
2x + 3y = 9
x +5y = 8
turns into
2x + 3y = 9
-2x - 10y = -16
OpenStudy (anonymous):
And now do I subtract?
jimthompson5910 (jim_thompson5910):
add the equations actually
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jimthompson5910 (jim_thompson5910):
since 2x + (-2x) = 0x
OpenStudy (anonymous):
so it would be -4x-13y=-25?
jimthompson5910 (jim_thompson5910):
you're adding the equations incorrectly (see my last post)
OpenStudy (anonymous):
x+13y=-25?
jimthompson5910 (jim_thompson5910):
2 + (-2) is the same as 2 - 2
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OpenStudy (anonymous):
I am lost again.
jimthompson5910 (jim_thompson5910):
2x + (-2x) is the same as 2x - 2x
OpenStudy (anonymous):
I understand that, so then why is 0x-13y=-25 wrong?
jimthompson5910 (jim_thompson5910):
3y + (-10y) is not -13y
jimthompson5910 (jim_thompson5910):
9 + (-16) is not -25
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OpenStudy (anonymous):
0x=-7y=-7?
jimthompson5910 (jim_thompson5910):
closer, but it should be
0x + (-7y) = -7
which is I'm sure what you meant to say
jimthompson5910 (jim_thompson5910):
so...
0x - 7y = -7
-7y = -7
y = ???
OpenStudy (anonymous):
y=1
OpenStudy (anonymous):
Now x=3
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jimthompson5910 (jim_thompson5910):
perfect on both
OpenStudy (anonymous):
Okay, can I try another one?
OpenStudy (anonymous):
6x+4y=42
-3x+3y=-6
6x+4y=42
-3x+3y=-6
_____________
3x+7y=26
Does that look right?
jimthompson5910 (jim_thompson5910):
were any variables eliminated?
OpenStudy (anonymous):
No..so do I subtract instead?
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jimthompson5910 (jim_thompson5910):
hint: look at the x terms and try to eliminate them
OpenStudy (anonymous):
is x=5
jimthompson5910 (jim_thompson5910):
Do you see how to get x = 5?
OpenStudy (anonymous):
well it had -9x=-48..I divided it.
jimthompson5910 (jim_thompson5910):
-9x = -48 doesn't lead you to x = 5
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OpenStudy (anonymous):
Is it wrong?
jimthompson5910 (jim_thompson5910):
add 6x and -3x to get 3x
That is NOT 0x
how can we change that -3x into something that adds to 6x to get 0x?
OpenStudy (anonymous):
multiply it
jimthompson5910 (jim_thompson5910):
by what
OpenStudy (anonymous):
2
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