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OpenStudy (anonymous):
Extraneous Solution?
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
anything to the 1/2 power is really a square root of that same group so (5x-4)^(1/2) is the same as sqrt(5x-4)
jimthompson5910 (jim_thompson5910):
does that help?
OpenStudy (anonymous):
Oh okay so it would be 5x-4=4x
OpenStudy (anonymous):
4x^2
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jimthompson5910 (jim_thompson5910):
sqrt(5x-4)-x = 0 sqrt(5x-4) = x 5x - 4 = x^2 0 = x^2 - 5x + 4 x^2 - 5x + 4 = 0
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