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Mathematics 25 Online
OpenStudy (anonymous):

What is the flaw in the student's proof? Justification 3 should be "Angle ABC = Angle BAD and Angle BAC = Angle ABD." Justification 4 should be "AB ÷ AD = AB ÷ AC because triangle ABC is similar to triangle ABD." Justification 2 should be "BC ÷ DC = AC ÷ BC because triangle ABC is similar to triangle BDC." Justification 1 should be "Angle ABC = Angle BCD and Angle BCA = Angle DBC."

OpenStudy (anonymous):

OpenStudy (anonymous):

@mathstudent55 will you help me ?

OpenStudy (mathstudent55):

I'm going over it now.

OpenStudy (mathstudent55):

Look at step 1. How do you prove two triangles similar using angles?

OpenStudy (anonymous):

@mathstudent55 2 angles most be congruent

OpenStudy (mathstudent55):

Right. Look at step 1. There are two angles of triangle shown to be congruent to two angles of triangle BDC. That means statement 1 and justification 1 are both correct.

OpenStudy (mathstudent55):

Now let's look at step 2.

OpenStudy (anonymous):

@mathstudent55 i dont get step 2 ....

OpenStudy (anonymous):

@mathstudent55 will you explain ?

OpenStudy (anonymous):

@Miyuru will you help ?

OpenStudy (mathstudent55):

Ok. Let's go over step 2 together.

OpenStudy (mathstudent55):

Look at justification 2.

OpenStudy (anonymous):

I am also confused on how BC^2 = AC x DC :(

OpenStudy (anonymous):

yeah right ! @Miyuru actually i think the mess is in the second one !

OpenStudy (mathstudent55):

I figured it out. Just follow along. This is justification 2: BC/DC = BC/AC

OpenStudy (mathstudent55):

When you have similar triangles, the lengths of the sides are proportional

OpenStudy (mathstudent55):

Let's look at the sides to see of this proportion is correct.

OpenStudy (mathstudent55):

|dw:1390718649262:dw|

OpenStudy (mathstudent55):

In the figure above, I separated the two triangles to show them in an easier to understand way.

OpenStudy (anonymous):

We have to look for the one that is wrong !

OpenStudy (mathstudent55):

Now I repositioned the smaller triangle to see more clearly the corresponding sides of the two similar triangles. |dw:1390718787885:dw|

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