Question

Please Help! Medal rewarded

an isosceles trapezoid has an area of 40m^2 and an altitude of 2m. its two bases have an ratio of 2 is to 3. What are the lengths of the bases and one diagonal of the trapezoid.

Answer 1

well if you know the altitude is 2m

then the area is

40 = h/2(a + b)

where h = altitude and a and b are the parallel sides

so

40 = 2/2(a + b)

so really

40 = a + b

the ratio is 2:3

so a = 2/5 of 40

b = 3/5 of 40

I'll leave you to do the calculations.

hope it helps