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If lim f(x)=5,and lim f(x)=6, then lim f(x)=
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where does x approach to in all these cases ?
2
F(x)=5 2^- and f(x)=6 is 2^+
right, ok. so lim x-> 2 f(x) will be defined if and only if lim x->2- f(x) and lim x-> 2+ f(x) are EQUAL. if they are not equal, then lim x->2 f(x) does not exist :)
im confused
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what confusion you have ? lim x->2- f(x) is LEFT HAND LIMIT lim x-> 2+ f(x) is RIGHT HAND LIMIT if left limit NOT = right limit, then the limit at that point does not exist.
oh i get it
thank you
most welcome ^_^
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