how many four-digit numbers are possible if the first digit cannot be zero and the number is divisible by 5?
a. 900
b. 1458
c. 1800
d. 2000
e. 4500

Question

how many four-digit numbers are possible if the first digit cannot be zero and the number is divisible by 5?
a. 900
b. 1458
c. 1800
d. 2000
e. 4500

anonymous · Answer

Look at how many numbers can be in each "place" of the four-digit number:

Thousands place: 9 possible digits (1-9)

Hundreds place: 10 possible digits

Tens place: 10 possible digits

Ones place: 2 possible digits (0 or 5, since it has to be divisible by 5)

Now you can multiply the the number of possible digits in each place to find the total number of possible combinations:

9 x 10 x 10 x 2=1800

Answer: c. 1800