Help please! :)

Write x^2 - 8x + 13 = 0 in the form (x - a)^2 = b, where a and b are integers.

(x - 4)^2 = 3

(x - 3)^2 = 2

(x - 2)^2 = 1

(x - 1)^2 = 4

Question

Help please! :)

Write x^2 - 8x + 13 = 0 in the form (x - a)^2 = b, where a and b are integers.

 (x - 4)^2 = 3

 (x - 3)^2 = 2

 (x - 2)^2 = 1

 (x - 1)^2 = 4

dumbcow · Answer

sorry
-take half of "b" coefficient, then square it
- subtract from "c" coefficient
- factor perfect square
-leaving --> (x- b/2)^2 + (c - b^2/4)

dumbcow · Answer

http://www.mathsisfun.com/algebra/completing-square.html

anonymous · Answer

the answer is first option 
(x-4)^2 =3
we need to get 8x through the squaring proceedure!!

which can be obtained only by squaring (x-4) = X^2 ((-2*4*x)) +16 =3
the three taken to LHS becomes -3 and 16-3 will give 13

anonymous · Answer

thanks guys!

anonymous · Answer

if it is an objective question (only answer matters) you can get away with the short cut!!
if it is a subjective one then then youll need to re trace your steps from the answer!!

Good luck!!