Question

can someone just check my answer fast?
factor: -x^2-x+20
i got: -x^2-x+20=-(x-4)(x+5)

Answer 1

@thomaster can you check this please?

Answer 2

I'm checking

Answer 3

I solved it. the answer is -x(x - 5 + 4)

Answer 4

can you show me how you got that please?

Answer 5

Sure.

Answer 6

?also would you mind checking my other work

Answer 7

In order to get -x^2 + x - 20, you need to make your initial value, (x^2) negative. So, by putting it outside the parenthesis, I am able to multiply -x by positve x inorder to get -x^2. You use the distributive property.
https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-factors-and-multiples/cc-6th-distributive-property/v/the-distributive-property
you can watch this video by Khanacademy. He will explain the ins and outs.

Answer 8

ok thanks. can you check my other answers?

Answer 9

27. Factor each expression –x^2-x+20
Reordered the terms: 20+-x+-x^2
Factored: (4+-x)(5+x)
Answer= (4+-x)(5+x)
28. –x^2+3x+40
Reordered the terms: 40+3x+-x^2
Factored: (8+-x)(5+x)
Answer: (8+-x)(5+x)
30. x^2+10x+-75
Reorder the terms: -75+10x+x^2
Factor: (-15+-x)(5+-x)
Answer: (-15+-x)(5+-x)

Answer 10

Well, I'm in a bit of a hurry, did you get the link to Khan academy?

Answer 11

I am going to have to go now, but if you have other questions, you can send me a message with them.

Answer 12

yeah, its ok if you cant do them.