Question

PLEASE HELP!!!
A clerk was asked to change a $10 bill. She returned 9 more dimes than nickels and twenty-one more quarters than dimes.

How many coins of each did she return?
Use the V.E.S.T steps please (variable, equation, solve. try it.)

Answer 1

x = nickels
x + 9 = dimes
(x + 9) + 21 = quarters

0.05x + 0.10(x + 9) + 0.25(x + 30) = 10.00
5x + 10(x + 9) + 25(x + 30) = 1000
5x + 10x + 90 + 25x + 750 = 1000
40x + 840 = 1000
40x = 160

x = 6 nickels
x + 9 = 15 dimes
x + 30 = 36 quarters

Answer 2

Alright im lost howd you get the answers??? @plohrr

Answer 3

if you let x = nickels

x + 9 = dimes , since the clerk returned 9 more dimes than nickels ,

and (x+9 ) + 21 = quarters , since the clerk gave here 21 more quarters than dimes.

Answer 4

yes i get that part

Answer 5

ok now since a nickel is 5/100, it is 0.05. and since a dime is 10/100, it is 0.10. and quarter is 0.25. do you get it so far

Answer 6

yes

Answer 7

just convert the parenthesis and add them into the equation, then combine like terms until it becomes a 2 step equation.

Answer 8

why did you add the 30 in tho

Answer 9

21 + 9 = 30. therefore that combined is 30 into the equation lol

Answer 10

oh lol okay and what I dont get is how you got the amount of coins for each one at the end.

Answer 11

ok. x = 6 right ?

Answer 12

yes

Answer 13

just add 9 to get 15 (# of dimes ), and add 30 to get 36 (# of quarters

Answer 14

but how do you know that x=6?

Answer 15

Oh nvm. i feel really stupid I get it now. lol

Answer 16

haha ok