what is the maximum y value on the graph -x^2+4x+4
the maximum value of y is at the vertex of this parabola. do you know how to find the vertex?
Is this a calculus class?
algebra. is the vertex (2,8) with the parabola opening downward
so the max y value is the y coordinate of the vertex.
Thank you. I think the vertex ends up being (2,16) so my answer would be 16
wait
the x coordinate of the vertex is found by -b/2a which in this case b=4 and a=-1, thus the x coordinate of the vertex is 2. if you plug 2 back into your original function, so x^2+4x_4|x=2, you do not get 16. I thought you were saying that the vertex was (2,8) earlier.. and that is right.. with the parabola opening downward since the coefficient of x is negative. had it been positive you would end up with a minimum value.
so 8 is the maximum y-value of x^2+4x+4
hope that wasn't too confusing.
nope makes sense, thank you. The second time I did it I forgot a negative sign
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